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Java.lang.IndexOutOfBoundsException

+2 votes

This exception is thrown in java when the index is higher than the size of a vector, arraylist, array etc... Ex:
ArrayList arr = new ArrayList(); arr.add("someStringHere"); for (int i = 0 ; i < 5 ; i++) { arr.get(i); }
The above example will throw IndexOutOfBoundsException, because the arraylist contains only 1 string and the index is going further than 0. (Also in Java the indices start with 0.)

requested 1 year ago by errorbase (169,970 points)
edited 1 year ago by onur

1 Solution

0 votes

The thrown exception shows the line number in which the problem has occured. The exception thrown for the above example is like this:
Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 1, Size: 1 at java.util.ArrayList.RangeCheck(Unknown Source) at java.util.ArrayList.get(Unknown Source) at SomePackage.SomeClass.main(SomeClass.java:16)
For this example the problem has occured in line 16. Additionally Index: 1 shows the index that we tried to reach and Size: 1 tells us the actual size of the variable.